9^2x+^5=81^x+1

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Solution for 9^2x+^5=81^x+1 equation: 



9^2x+^5=81^x+1

We move all terms to the left:

9^2x+^5-(81^x+1)=0

We add all the numbers together, and all the variables

9^2x-(81^x+1)=0

We get rid of parentheses

9^2x-81^x-1=0

We move all terms containing x to the left, all other terms to the right

9^2x-81^x=1

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